The minimum energy requried to overcome the attractive forces between an electron and the surface of Ag metal is `5.52xx10^(-19)`J. what will be the maximum kinetic energy of electrons ejected out from Ag which is being exposed to UV light of `lamda=360`Ã…?

Explanation

Energy of the photons absorbed
`E = (hc)/(lambda) = (6.626 xx 10^(-27) xx 3xx 10^(10))/(360 xx 10^(-8))`
`= 5.52 xx 10^(-11)` erg
`= 5.52 xx 10^(-18)J`
E (photon) = Work function `+K.E`
`K.E = 5.52 xx 10^(-18) - 7.52 xxx 10^(-19)`
`= 47.68 xx 10^(-19)J`