Threshold wavelength of a metal is 230 nm. What will be the kinetic energy of photoelectrons ejected when the metal is irradiated with wavelength 180 nm? `(h = 6.626 xx 10^(-34)Jsec)`

Explanation

To find the kinetic energy of photoelectrons ejected when a metal is irradiated with a wavelength of 180 nm, we can use the photoelectric equation:

\[ E = \frac{hc}{\lambda} - \phi \]

Where:
- \(E\) is the kinetic energy of the photoelectrons,
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