A microscope using suitable photons is employed to an electron in an atom within a distance of `0.1 Å`. What is the uncertainty involved in the measurment of its velocity? Mass of electron `= 9.11 xx 10^(-31) kg` and `h = 6.626 xx 10^(-34) J s`

Explanation

`Deltax. Deltap = (h)/(4pi) rArr Delta x.m Deltav = (h)/(4pi), Deltav = (h)/(4pi Delta xm)`
`Delta v = (6.626 xx 10^(-34)Js)/(4xx 3.14 xx 0.1 xx 10^(-10)m xx 9.11 xx 10^(-31)kg)`
`= 0.579 xx 10^(7)ms^(-1) (1J = 1kg m^(2)s^(-2)) = 5.79 xx 10^(6)ms^(-1)`