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During ionisation of copper atom, the qu...

During ionisation of copper atom, the quantum numbers of electron removed maybe

A

`n = 4 l = 1 s= +(1)/(2)`

B

`n = 3 l = 0 s =- (1)/(2)`

C

`n = 4 l = 0 s = +(1)/(2)`

D

`n = 4 l = 2 s =- (1)/(2)`

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The correct Answer is:
C
`e^(-)` removed from 4s orbital
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