When a metal is irradiated with light of frequency `4.0 xx 10^(16)s^(-1)` the photo electrons emitted has six times the K.E as the K.E of photo electron emitted when the metal was irradiated with light of frequency `2.0 xx 10^(16)s^(-1)`. Calculate the critical frequency of the metal.

Options

A. `2.0 xx 10^(16)s^(-1)`
B. `1.6xx 10^(16)s^(-1)`
C. `3.0xx 10^(16)s^(-1)`
D. `4.2 xx 10^(16)s^(-1)`

Answer

B

Explanation

`(K.E_(2))/(K.E_(1)) = (v_(2)-v_(0))/(v_(1)-v_(0))`