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The Ratio of m^(th) to n^(th) wavelength...

The Ratio of `m^(th)` to `n^(th)` wavelength of Lyman series in H-spectrum is equal to

A

`(lambda_(m))/(lambda_(n)) = ((m^(2)-1)xxn^(2))/((n^(2)-1)xxm^(2))`

B

`(lambda_(m))/(lambda_(n)) = ((n^(2)-1)xxm^(2))/((m^(2)-1)xxn^(2))`

C

`(lambda_(m))/(lambda_(n)) =((m+1)^(2))/((n+1)^(2)) xx ((n+1)^(2)-1)/((m+1)^(2)-1)`

D

`(lambda_(m))/(lambda_(n)) =((n+1)^(2))/((m+1)^(2)) xx ((m+1)^(2)-1)/((n+1)^(2)-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`bar(v) =(1)/(2)=R[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
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