A single electron in an ion has ionization energy equal to `217.6eV`. What is the total number of neutrons present in one ion of it?

Options

A. 2
B. 4
C. 5
D. 9

Answer

C

Explanation

Ionization energy `-217.6 =- 13.6 xx (Z^(2))/(1^(2)), Z = 4m`
So, it is `._(4)^(9)Be^(3+)`, no of neutrons `9 -4 = 5`