Neon gas emits at 616 nm. The distance travelled by this radiation in 30 sec is.

Options

A. `9 xx 10^(7)m`
B. `9 xx 10^(9)m`
C. `4.5 xx 10^(9)m`
D. `7 xx 10^(9)m`

Explanation

To find the distance traveled by the neon gas radiation in 30 seconds, we can use the formula for distance, which is:

\[ \text{Distance} = \text{Speed} \times \text{Time} \]

### Step 1: Identify the speed of light
The speed of light in a vacuum is approximately:

\[ c = 3 \times 10^8 \, \text{meters/second} \]

### Step 2: Identify the time duration
The time duration given in the question is:

\[ t = 30 \, \text{seconds} \]

### Step 3: Calculate the distance
Now, we can substitute the values into the distance formula:

\[ \text{Distance} = c \times t \]
\[ \text{Distance} = (3 \times 10^8 \, \text{m/s}) \times (30 \, \text{s}) \]

### Step 4: Perform the multiplication
Calculating the above expression:

\[ \text{Distance} = 3 \times 30 \times 10^8 \]
\[ \text{Distance} = 90 \times 10^8 \, \text{meters} \]
\[ \text{Distance} = 9 \times 10^9 \, \text{meters} \]

### Final Answer
The distance traveled by the neon gas radiation in 30 seconds is:

\[ 9 \times 10^9 \, \text{meters} \]

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