An iodine molecule dissociates into atom after absorbing light of wavelength `4500`Å. If quantum of radiation is absorbed by each molecule calculate the kinetic energy of iodine (Bond energy of `I_(2)` is `240`` kJ mol^(-1))`

Options

A. `2.16 xx 10^(-20)J`
B. `4.1 xx 10^(-20)J`
C. `3.12 xx 10^(-14)J`
D. `2.16 xx 10^(-22)J`

Answer

B

Explanation

B.E for 1 molecule `=(240 xx 10^(3))/(6 xx 10^(23)) = 40 xx 10^(-20)J`
`4 xx 10^(-19)J`
Energy of incident light `E = (hc)/(lambda) = 4.41 xx 10^(-19)J`
`K.E. = 0.41 xx 10^(-19) = 4.1 xx 10^(-20)J`