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When electromagnetic radiation of wavelength 300 nm falls on the surface of sodium, electrons are emitted with kinetic energy of `1.68 xx 10^(5) J "ml"^(-1)`. What is the minimum energy needed to remove an electron from sodium ? What is the maximum wavelength that will cause a photoelectron to be emitted.

A

`51.7nm`

B

`517nm`

C

`427nm`

D

`62nm`

Text Solution

Verified by Experts

The correct Answer is:
B
`hv = W +K.E, W = (hc)/(lambda) - K.E`
`W = (hc)/(lambda_(0)) rArr lambda_(0) = (hc)/(W)`
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