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Energy of an electron is givem by E = - ...

Energy of an electron is givem by `E = - 2.178 xx 10^-18 J ((Z^2)/(n^2))`. Wavelength of light required to excited an electron in an hydrogen atom from level `n = 1` to `n = 2` will be
`(h = 6.62 xx 10^-34 Js` and `c = 3.0 xx 10^8 ms^-1`).

A

`1.214 xx 10^(-7)m`

B

`2.816 xx 10^(-7)m`

C

`6.5 xx 10^(-7)m`

D

`8.5 xx 10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
A

`DeltaE = (hc)/(lambda) = 2.178 xx 10^(-18) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`
`(6.6256 xx 10^(-34) xx 3 xx 10^(8))/(lambda) = 2.178 xx 10^(-18) ((1)/(1^(2))-(1)/(2^(2)))`
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Energy of an electron is given by E = - 2.178 xx 10^-18 J ((Z^2)/(n^2)) . Wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be (h = 6.62 xx 10^-34 Js and c = 3.0 xx 10^8 ms^-1 ).

Energy of an electron in an excited hydrogen atom is -3.4eV . Its angualr momentum will be: h = 6.626 xx 10^(-34) J-s .

The ionisation energy of hydrogen atom is 1.312xx10^(6) J "mol"^(-1) . Calculate the energy required to excite an electron in a hydrogen atom from the ground state to the first excited state.

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