The ionization enthalpy of hydrogen atom is `1.312 xx 10^6 J mol^-1`. The energy required to excite the electron in the atom from `n= 1` to `n = 2` is :

Options

A. `8.51 xx 10^(5)J mol^(-1)`
B. `6.56 xx 10^(5)J mol^(-1)`
C. `7.56 xx 10^(5)J mol^(-1)`
D. `9.84 xx 10^(5)J mol^(-1)`

Answer

D

Explanation

`DeltaE = E_(2) - E_(1) [:. I.E. =- E_(1)]`
`= (-1.312 xx 10^(6))/(2^(2))-((-1.312xx10^(6))/(1))`