In `psi_(321)` the sum of angular momentum, spherical nodes and angular node is:

Options

A. `(sqrt(6)h+4pi)/(2pi)`
B. `(sqrt(6h))/(2pi)+3`
C. `(sqrt(6h)+2pi)/(2pi)`
D. `(sqrt(6h)+8pi)/(2pi)`

Answer

A

Explanation

`psi_(321): n = 3, i=2, m= 1`
Angular momentum `=(h)/(2pi) sqrt(l(l+1)) = (sqrt(6)h)/(2pi)`
Spherical nodes `= 3 - 2 -1 = 0`, Angular node `=2`
Sum of all the above `=(sqrt(6)h)/(2pi) +2 = (sqrt(6h)+4pi)/(2pi)`