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The angular momentum of an electron due...

The angular momentum of an electron due to its spin is given as ………..

A

`sqrt(s(s+1))(h)/(2pi)`

B

`s(s+1)(h)/(2pi)`

C

`(h)/(2pi)`

D

`s(s+1)(2pi)/(h)`

Text Solution

Verified by Experts

The correct Answer is:
A
spin angular momentum `= sqrt(s(s+D)) (h)/(2pi)`
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