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When the frequency of light incident an ...

When the frequency of light incident an a metallic plate is doubled , the KE of the emitted photoelectrons will be :

A

Doubled

B

Halved

C

Increased out more than doubled of the previous KE

D

Remains unchanged

Text Solution

Verified by Experts

The correct Answer is:
C
`hv = hv_(0) +KE` threshold frequency of metal is constant
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