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Electronmagnetic radiations having lambd...

Electronmagnetic radiations having `lambda=310Å`are subjected to a metal sheet having work function `=12.8eV`. What will be the velocity of photoelectrons with maximum Kinetic Energy….

A

0, no emission will occur

B

`4.352 xx 10^(6)m//s`

C

`3.09 xx 10^(6)m//s`

D

`8.72 xx 10^(6)m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
`(hc)/(lambda) = phi +(1)/(2)mv^(2)`
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