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The ratio of slopes of K(max) vs. V and ...

The ratio of slopes of `K_(max)` vs. V and `V_(0)` vs. v curves in the photoelectric effect gives (v= freqency. `K_(max)`= maximum kinetic energy, `V_(0)`=stopping potential) :

A

Charge of electron

B

Planck's constant

C

Work function

D

The ratio of Planck's constant of electronic charge

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The correct Answer is:
A
`KE = hv - hv_(0), eV_(0) = hv - hv_(0)`
ratio of slopes `=(h)/((h//e))=e`
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