If the 2nd excitation potential for a Hydrogen like atom in a simple is `108.9V`. Then the series limit of the paschen series for this atom is:

Options

A. `R_(H)`
B. `(R_(H))/(3^(2))`
C. `(3^(2)R_(H))/(4^(2))`
D. `3^(2)R_(H)`

Answer

A

Explanation

`DeltaE = 13.6 xx z^(2) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))] , z = 3`
`barunderset(oo)(v) =R_(H).z^(2)[(1)/(3^(2))] = R_(H)`