If `lambda_(1)` and `lambda_(2)` denote the de-Broglie wavelength of two particles with same masses but charges in the ratio of `1:2` after they are accelerated from rest through the same potential difference, then

Options

A. `lambda_(1) = lambda_(2)`
B. `lambda_(1) lt lambda_(2)`
C. `lambda_(1) gt lambda_(2)`
D. `lambda_(1) lt sqrt(lambda_(2))`

Answer

C

Explanation

`lambda = (h)/(sqrt(2.m.q.v))`