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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in `2s`-orbital is

A

`(h)/(4pi)`

B

zero

C

`(h)/(2pi)`

D

`(sqrt(2)h)/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
`L = sqrt(l(l+1)) (h)/(2pi)`
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