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For a 'd' electron, the orbital angular ...

For a 'd' electron, the orbital angular momentum is `(h =(h)/(2pi))`

A

`sqrt(6)h`

B

`sqrt(2)h`

C

h

D

2h

Text Solution

Verified by Experts

The correct Answer is:
A
`L = sqrt(l(l+1))(h)/(2pi)`
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