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The Schrodinger wave equation for hydrog...

The Schrodinger wave equation for hydrogen atom is `Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0))` , where `a_(0)` is Bohr's radius . If the radial node in 2s be at `r_(0)` , then `r_(0)` would be equal to :

A

`(a_(0))/(2)`

B

`2a_(0)`

C

`sqrt(2)a_(0)`

D

`(a_(0))/(2)`

Text Solution

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The correct Answer is:
B
At node `Psi^(2) =0` hence `Psi =0, :. R = 2a_(0)`
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