A compound of vanadium possesses a magne...

A compound of vanadium possesses a magnetic moment of `1.73BM`. The oxidation state of vanadium in this compounds is:

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The correct Answer is:

`mu_(s) = sqrt(n(n+2))` where `n = 1`

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A compound of vanadium has a magnetic moment of 1.73 BM. The electronic configuration of vanadium ion in the compound is:

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