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An alpha particle of momentum p is bomba...

An `alpha` particle of momentum p is bombarded on the nucleus, the distance of the closest approach is r, if the momentum of `alpha`-particle is made to 6p, then the distance of the closest approach becomes

A

`4r`

B

`2r`

C

`16r`

D

`(r)/(36)`

Text Solution

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The correct Answer is:
D
`(p^(2))/(2m) =(q_(1)q_(2))/(r)` at closes approach
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