Ground state energy of H-atom is `(-E_(1))`,t he velocity of photoelectrons emitted when photon of energy `E_(2)` strikes stationary `Li^(2+)` ion in ground state will be:

Options

A. `v = sqrt((2(E_(p)-E))/(m))`
B. `v =sqrt((2(E_(p)+9E))/(m))`
C. `v = sqrt((2(E_(p)-9E))/(m))`
D. `v = sqrt((2(E_(p)-3E))/(m))`

Answer

C

Explanation

`E_(0) =E_(0) +(1)/(2)mv^(2) rArr v = sqrt((2(E_(p)-E_(0)))/(m))` But `E_(0) = 9E`