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4000 overset(0)(A) photons is used to br...

`4000 overset(0)(A)` photons is used to break the iodine molecule, then the % of energy converted to the K.E of iodine atoms if bond dissociation energy of `I_(2)` molecule is `246.5 kJ//mol`

A

`8%`

B

`12%`

C

`17%`

D

`25%`

Text Solution

Verified by Experts

The correct Answer is:
C

`E = (hc)/(lambda) = 3.1 eV = 297 kJ//"mole"`
`:. E = E_(0)+KE`
% energy converted to `KE = (297 - 246.5)/(297) = 17%`
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