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What is the frequency of revolution of e...

What is the frequency of revolution of electron present in `2nd` Bohr's orbit of `H-` atom ?

A

`1.016 xx 10^(16)s^(-1)`

B

`4.065 xx 10^(16)s^(-1)`

C

`1.626 xx 10^(15)s^(-1)`

D

`8.13 xx 10^(16)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`f_(n,z) = (V_(n,z))/(2pir_(n,z))`
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