What is the angular velocity `(omega)` of an electron occupying second orbit of `Li^(2+)` ion?

Options

A. `(8pi^(3)me^(4))/(h^(3))K^(2)`
B. `(8pi^(3)me^(4))/(9h^(3))K^(2)`
C. `(64)/(9) xx (8pi^(3)me^(4))/(9h^(3))K^(2)`
D. `(9pi^(3)me^(4))/(h^(3))K^(2)`

Answer

D

Explanation

`omega_(n,z) = 2pi f_(n,z) = (V_(n,z))/(r_(n,z))`