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Light from a discharge tube containing H...

Light from a discharge tube containing H-atoms in some excited state, falls on the metallic surface of metal Na.The KE of the fastest photo-electron was found to be fastest photo-electron was found to be `10.93eV`. If `He^(+)` ions were present in the same excited state, the KE of the fastest photo-electron would have been `49.18eV`. Determine the excited state orbit number and work function of Na.

A

`2,18.2ev`

B

`4,1.82ev`

C

`3,16ev`

D

`2,1.6ev`

Text Solution

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The correct Answer is:
B
`E_(1) = E_(0) +10.93, E_(2) = E_(0) +49.18`
`[13.6 xx 2^(2) - 13.6 xx 1^(2)] [(1)/(1^(2))-(1)/(n^(2))]`
`= E_(2) - E_(1) = Delta E = 38.25`
`:. n = 4, :. E_(1) = 12.75 & E_(0) = 1.82 eV`
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