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The ratio of magnetic moments of Fe(III)...

The ratio of magnetic moments of `Fe(III)` and `Co(II)` is:

A

`sqrt(5):sqrt(7)`

B

`sqrt(35):sqrt(15)`

C

`7:3`

D

`sqrt(24):sqrt(15)`

Text Solution

Verified by Experts

The correct Answer is:
B
`mu_(s) = sqrt(n(n+2)) BM`
In `Fe(III), n = 5`, In `CO(II), n = 3`
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