1st excitation potential for the H-like (hypothetical) sample is 24 V. Then:

Options

A. Ionisation energy of the sample is `36eV`
B. Ionisation energy of the sample is `32 eV`
C. Binding energy of 3rd excited state is `2eV`
D. 2nd excitation potential of the sample is `(32 xx 8)/(9)eV`

Answer

B, C, D

Explanation

Ist excitation potential
`13.6 xx z^(2) [1-(1)/(2^(2))] = 24eV, 13.6 xx z^(2) = I.E = 32 eV`