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An excited state of H atom emits a photo...

An excited state of H atom emits a photon of wavelength `lamda` and returns in the ground state. The principal quantum number of excited state is given by:

A

`sqrt(((lambdaR-1))/(lambdaR))`

B

`sqrt(lambdaR(lambdaR-1))`

C

`sqrt((lambdaR)/((lambdaR-1)))`

D

`sqrt(lambdaR(lambdaR+1))`

Text Solution

Verified by Experts

The correct Answer is:
C

`(1)/(lambda) = R ((1)/(1)-(1)/(n_(2)^(2)))`
`n_(2)^(2) = (R lambda)/(R lambda -1), n_(2) = sqrt((R lambda)/(R lambda -1))`
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