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For a saturated solution of AgCl at 25^(...

For a saturated solution of AgCl at `25^(@)C,k=3.4xx10^(-6) ohm^(-1)cm^(-1)` and that of `H_(2)O` (l) used is `2.02xx10^(-6) ohm^(-1) cm^(-1),lambda_(m)^(@)` for AgCl is 138 `ohm^(-1) cm^(2) "mol"^(-1)` then the solubility of AgCl in "mole"s per litre will be:

A

`10^(-5)`

B

`10^(-10)`

C

`10^(-14)`

D

`10^(-16)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda^@=1000xx(K_(Sol)-k_(H_2O))/S`
`138=(1000xx(3.4-2.02)xx10^(-6))/S`
`S=1xx10^(-5)`
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