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Statement-1: For the reaction: Ni^(2+)...

Statement-1: For the reaction:
`Ni^(2+)+2e^(-)rarrNi` and `Fe^(2+)+2e^(-)rarrFe`
`rArr E_(Fe^(2+)|Fe)^(@)ltE_(Ni^(2+)|Ni)^(@)` and `E_("Red")^(@)gt0`
`rArr` So Fe electrode is cathode and Ni electrode is anode.
Statement-2: If `DeltaG^(@) lt0` and `E_("Cell")^(@)lt0`, then , cell is feasible.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-2

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(Ni^(+2)|Ni)^@=-0.24 " " E_(Fe^(+2)|Fe)^@=-0.44`
`E_(Cell)^@=E_(Fe|Fe^(+2))^@+E_(Ni^(+2)|Ni)^@`
=0.44-0.24=0.20
Fe electrode Anode, Ni electrode cathode
`DeltaG lt 0 " " E_(Cell)gt0` For working of cell
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