At 0.04 M concentration, the molar conductivity of solution of an electrolyte is `5000 Omega^(-1)cm^(2) mol^(-1)` while at 0.01 M concentration the value is `5100 Omega^(-1)cm^(2)mol^(-1)`. Making necessary assumption (Taking it as strong electrolyte) find the molar conductivity at infinite dilution and write percentage dissociation of strong electrolyte at 0.04 M.

Answer

96

Explanation

From the graph we can see the `lambda_M^oo` value of `5200 Omega^(-1) cm^2 mol^(-1)` Hence
`alpha=5000/5200=0.9615=0.96`