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To prepare a buffer solution of pH=4.04,...

To prepare a buffer solution of pH=4.04, amount of Barium acetate to be added to 100 mL of 0.1 M acetic acid solution `[pK_b(CH_(3)COO^(-))=9.26]` is:

A

0.05 mole

B

0.025 mole

C

0.1 mole

D

0.005 mole

Text Solution

Verified by Experts

The correct Answer is:
B
For the buffer solution of `CH_3COOH & CH_3COO^(-)`
`pH=pK_a + "log" ([CH_3COOH])/([CH_3COO^(-)])" " implies 4.04=4.74+"log" ((100xx0.1))/(m."moles of " CH_3COO^(-))`
`implies` m.moles of `CH_3COO^(-)=50 " " therefore` moles of `(CH_3COO)_2` Ba required =0.025.
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