Match the following :
If `k_a` of HCN=`5xx10^(-10), k_a` of HOCN =`3.2xx10^(-4)`, `k_b` of `NH_3=1.8xx10^(-5)`, `k_a` of `CH_3COOH=1.8xx10^(-5)`
(All data at `25^@ C`)
`{:("Column-I","Column-II"),((A)10^(-2) M NaCN, (p)pH gt 7),((B)"100 ml of" 10^(-1) M NaCl + "100 ml of"10^(-1) M "HCl+300 ml of" 10^(-1)M NaOH ,(q)pH ne7),((C )10^(-1) "M HCl +" 10^(-1) "M HCN",(r)pH lt 7),((D)10^(-1) M NH_4OCN,(s)pH=7),(,(t)"pOH lt 7"):}`

Answer

A-p,q,t ; B-p,q,t ; C-q,r ; D-q,r

Explanation

(A)anionic hydrolysis leads to formation of `OH^(-)` due to which `pH gt7`
(B)`(N_1V_1)_(NaOH) gt (N_2V_2)_(HCl)`
( C)strong acid + weak acid, so `pH lt 7`
(D) Hydrolysis of cation leads to the formation of `H^+` due to which `pH lt 7`