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A solution of x moles of sucrose in 100g...

A solution of `x` moles of sucrose in `100`grams of water freeze at `-0.2^(@)C` As. Ice separates the freezing point goes down to `0.25^(@)C`. How many grams of ice would have separated ?

A

18 grams

B

20 grams

C

25 grams

D

23 grams

Text Solution

Verified by Experts

The correct Answer is:
B
`("molality")_f=(x xx1000)/100=0.2/K_f`…(1)
`("molality")_f=(x xx1000)/w=0.25/K_f`…(2)
`(1)//(2)`
So, `0.2/0.25=w/100 implies so" " w=80 gm`
Hence ice separated =20 gm
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