In `10^3` Litre sample of hard water `CaSO_4 and MgSO_4` is present.If elevation in Boiling point is `0.000052^@C`.Calculate the degree of Hardness of hard water .(`K_b` for `H_2O=0.52`)

Answer

5

Explanation

`DeltaT_b=DeltaT_(b_1)=DeltaT_(b_2)`
`DeltaT_b=0.0000104=(m_1i_1+m_2i_2)xxk_b`
`{:(CaSO_4,MgSO_4),(i=i_1,i'=i_2),(n=n_1,n'=n_2):}`
`0.000052=((n_1+n_2)xx0.52xx2)/10^6xx1000`
`n_1+n_2=0.05`
for degree of Hardness
`n_(CaSO_4)+n_(MgSO_4)=n_(CaCO_3) " " n_1+n_2=n_(CaCO_3)`
`n_(CaCO_3)=0.05`
`m_(CaCO_3)=0.05xx100=5` gm
degree of hardness=`5/10^6xx10^6=5` ppm