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In the formation of HBr from H2 & Br2 f...

In the formation of HBr from `H_2` & `Br_2` following mechanism is observed.
(A)`Br_2hArr2Br.` Equilibrium step
(B)`H_2+Br.toHBr+H.` slow step
( C)`H.+Br_2toHBr+Br.` Fast step
Calculate the rate of reaction, if concentration of hydrogen is twice that of bromine and the rate constant is equal to one rutherford.Concentration of bromine is 1M.

A

`2xx10^6` dps

B

`10xx10^9` dps

C

`20.2xx10^10` dps

D

`4xx10^2` dps

Text Solution

Verified by Experts

The correct Answer is:
A
1-Rutherford=`10^6` dps
Rate =`k[H_2]^1[Br_2]^(1//2)`
Rate = `10^6[2]^1[1]^(1//2)=2xx10^6` dps
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