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Consider the following case of competing...

Consider the following case of competing `1^(st)` order reactions.

After the start of the reaction at t=0 with only A,the [C] is equal to the [D] at all time.The time in which all three concentrations wil be equal is given by :

A

`t=1/(2k_1)ln3`

B

`t=1/(2k_2)ln3`

C

`t=1/(3k_1)ln2`

D

`t=1/(3k_2)ln2`

Text Solution

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The correct Answer is:
A,B

`k_1=k_2`
`implies 2/3rd` of A has reacted for [A] =[C]=[D]
`:. K_1+k_2=1/t "In"([A]_0)/(1/3[A]_0)`
`implies t=1/(k_1+k_2)"In" 3=1/(2k_1)"In"3=1/(2k_2)"In"3`
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