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If (dx)/(dt)=k[H(3)O^(+)]n and rate be...

If `(dx)/(dt)=k[H_(3)O^(+)]n`
and rate becomes 100 times when pH changes from 2 to 1 Hence order of reactions is

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`(dx)/(dt)=k[H^+]^nimplies r_1=k[10^(-2)]^nimplies r_2=k[10^(-1)]^n`
`r_1=k[10^(-2n)]`…(i)
`100 r=k(10^(-n))`…(ii)
Divide:(i)/(ii) `implies 1/100=10^(-n)implies n=2`
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