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In a iodomeric estimation, the following...

In a iodomeric estimation, the following reactions occur
`2Cu^(2+)+4i^(-) to Cu_(2)I_(2)+I_(2), I_(2)+2Na_(2)S_(2)O_(3) to 2NaI+Na_(2)S_(4)O_(6)`
0.12 mole of `CuSO_(4)` was adde to excess of KI solution and the liberated iodine required 120mL of hypo. The molarity of hypo soulution was:

A

2

B

`0.20`

C

`0.1`

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
D
Moles of pure `CuSO_4=0.12`=moles of `Na_2S_2O_3` reacted with `l_2`
Moles of `Na_2S_2O_3=120xx10^(-3)xxM=0.12`
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In iodometric estimation of Cu^(2+) ion, the following reaction took place 2Cu^(2+)+4ItoCu_(2)I_(2)+I_(2) I_(2)+2Na_(2)S_(2)O_(3)to2NaI+Na_(2)S_(4)O_(6) If 100mL OF CuSO_(4) solution added to excess KI requires 50mL of 0.2M Na,S_(2)O_(3) the molarity of CuSO_(4) solution is :

In this reaction 2Na_(2)S_(2)O_(3)+I_(2)=Na_(2)SO_(4)O_(6)=2NaI_(2) acts as:

For the following reaction I_(2)+2Na_(2)S_(2)O_(3)rarr2NaI+Na_(2)S_(4)O_(6) The incorrect statement is

Na_(2)S_(2)O_(3)+I_(2)rarr Product is

Find the n factor of Na_(2) S_(2) O_(3) in the following reactions. Na_(2) S_(2) O_(3) + I_(2) rarr NaI + Na_(2) S_(4) O_(6)

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