0.1M solution of KI reacts with excess of `H_(2)SO_(4)` and `KIO_(3)` solutions, according to equation
`5I^(-)+IO_(3)^(-)+6H^(+)to3I^(2)+3H_(2)O`, which of the following statements is /are correct:

Options

A. 400 ml of the KI solution react with 0.004 mole of `KIO_3`
B. 100 ml of the KI solution reacts with 0.006 mole of `H_2SO_4`
C. 0.5 litre of the KI solution produced 0.005 mole of `I_2`
D. Equivalent weight of `KIO_3` is equal to `(("Molecular Weight")/5)`

Answer

B,D

Explanation

`5I^(-) + IO_3^(-) +6H^(+)to3I_2 + 3H_2O`
`("moles of" KI "used")/("moles of" KIO_3 "used")=5`
valency factor of `KIO_3=5`
`:. E_(KIO_3)=("mol. Wt.")/5`