Assertion: In the redox reaction `8H^(+)(aq)+4NO_(3)^(-)+6Cl^(-)+Sn(s) rarr SnCl_(6)^(2-)+4NO_(2)+4H_(2)O`. the reducing agent is `Sn(s)`.
Reason In balacing half-reaction, `S_(2)O_(3)^(2-) rarr S(s)`, the number of electrons added on the left is `4`.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Answer

B

Explanation

`Sn(0to+4)`
It undergoes oxidation, so it is the reducing agent.
`S_2O_3^(2-)+6H^(+)+4e^(-)to2S+3H_2O`