When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume becomes 60 L. Calculate entropy change for the process `(C_(p.m)=30.96 J "mole"^(-1) K^(-1))`

Options

A. `80.2 J.k^(-1) "mol"^(-1)`
B. `62.42 J.k^(-1) "mol"^(-1)`
C. `120xx10^2 J.k^(-1) "mol"^(-1)`
D. `27.22 J.k^(-1) "mol"^(-1)`

Answer

D

Explanation

`(P_1V_1)/T_1=(P_2V_2)/T_2`
`T_2/T_1=6/3`
`DeltaS=2.303xxn{C_p"log"_10T_2/T_1+R"log"_10P_1/P_2}`
`DeltaS=2.303xx1{30.96"log"_10 6/3 +R"log"_10 20/10}`
`DeltaS=27.22 J.K^(-)1 mol^(-)1`