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The unit of equilibrium constant KC of a...

The unit of equilibrium constant `K_C` of a reaction is `"mol"^(-2) boat^2`.For this reaction, the product concentration increases by

A

increasing the pressure

B

Lowering the temperature

C

Lowering the pressure

D

Both B and C

Text Solution

Verified by Experts

The correct Answer is:
A

`K_C=("mole"//"litre")^(Deltan)`
where `Deltan`=no of moles on product side-no .of moles on reactant side
Hence `Deltan=-2`
so moles on reactant side `gt` moles on product side
so on increasing pressure reaction will get shifted in forward direction
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