At 1400 K, `K_c=2.5xx10^(-3)` for the reaction `CH_4(g)+2H_2S(g)hArrCS_2(g)+4H_2(g)`.A 10.0 L reaction vessel at 1400 K contains 2.00 mole of `CH_4`.3.0 mole of `CS_2`,3.0 mole of `H_2` and 4.0 mole of `H_2S`.Then

Options

A. This reaction is at equilibrium with above concentrations
B. The reaction will proceed in forward direction to reach equilibrium
C. The reaction will proceed in backward direction to reach equilibrium
D. The information is insufficient to decide the direction of progress of reaction

Answer

C

Explanation

`Q_c=((3/10)^4(3/10))/((2/10)(4/10)^2)=243/32xx10^(-2)=7.59xx10^(-2)gtK_c`
So, reaction will proceed in backward direction