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The volume occupied by 2.0 mole of N2 at...

The volume occupied by 2.0 mole of `N_2` at 200 K and 8.21 atm pressure, if `(P_CV_C)/(RT_C)=3/8 and (P_rV_r)/T_r=2.4`, is

A

1.8 L

B

`(5/8)` L

C

12.8 L

D

3.6 L

Text Solution

Verified by Experts

The correct Answer is:
D
`(P_rV_r)/T_r=P/T_c V_m/V_c.T_c/T=(PV_m)/(RT).(RT_C)/(P_CV_C)`
`(PV_m)/(RT)=2.4xx(3/8)`
So `V_m=(0.0821xx200)/8.21xx0.9=1.82` So Volume of 2 moles =3.6 L
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