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The ration of the e//m (specific charge)...

The ration of the `e//m` (specific charge) values of an electron and an `alpha-"particle"` is

A

`2:1`

B

`1:1`

C

`1:1`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`(e/m)_e=e/m_e(e/m)_alpha=(2e)/m_alpha=(4e)/(4m_p)=(2e)/(4xx1840m_e)implies ((e//m)_e)/((e//m)_alpha)=3680`
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